Javascript debugger
Website design
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tidyNode->isPhp
Returns true if this node is PHP
()
bool tidyNode->isPhp ( )
Returns TRUE if the current node is PHP code, FALSE otherwise.
Example 2557. get the PHP code from a mixed HTML/PHP document
<?php
$html = <<< HTML
<html><head>
<?php echo '<title>title</title>'; ?>
</head>
<body>
<?php
echo 'hello world!';
?>
</body></html>
HTML;
$tidy = tidy_parse_string($html);
$num = 0;
get_php($tidy->html());
function get_php($node) {
// check if the current node is PHP code
if($node->isPhp()) {
echo "\n\n# PHP node #" . ++$GLOBALS['num'] . "\n";
echo $node->value;
}
// check if the current node has childrens
if($node->hasChildren()) {
foreach($node->child as $child) {
get_php($child);
}
}
}
?>The above example will output:
# PHP node #1
<?php echo '<title>title</title>'; ?>
# PHP node #2
<?php
echo 'hello world!';
?>
Note:
This function was named tidy_node->is_php() in PHP 4/Tidy 1.