Javascript debugger
Website design
↑
The pattern to search for, as a string.
The input string.
If matches is provided, then it is filled with
the results of search. $matches[0]
will contain the
text that matched the full pattern, $matches[1]
will have the text that matched the first captured parenthesized
subpattern, and so on.
flags can be the following flag:
PREG_OFFSET_CAPTURE
0
and its string offset into
subject at index 1
.
Normally, the search starts from the beginning of the subject string. The optional parameter offset can be used to specify the alternate place from which to start the search (in bytes).
Using offset is not equivalent to passing
substr($subject, $offset)
to
preg_match() in place of the subject string,
because pattern can contain assertions such as
^, $ or
(?<=x). Compare:
<?php
$subject = "abcdef";
$pattern = '/^def/';
preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE, 3);
print_r($matches);
?>
The above example will output:
Array
(
)
while this example
<?php
$subject = "abcdef";
$pattern = '/^def/';
preg_match($pattern, substr($subject,3), $matches, PREG_OFFSET_CAPTURE);
print_r($matches);
?>
will produce
Array
(
[0] => Array
(
[0] => def
[1] => 0
)
)
preg_match() returns the number of times
pattern matches. That will be either 0 times
(no match) or 1 time because preg_match() will stop
searching after the first match. preg_match_all()
on the contrary will continue until it reaches the end of
subject.
preg_match() returns FALSE
if an error occurred.
Version | Description |
---|---|
4.3.3 | The offset parameter was added |
4.3.0 |
The PREG_OFFSET_CAPTURE flag was added
|
4.3.0 | The flags parameter was added |
<?php
// The "i" after the pattern delimiter indicates a case-insensitive search
if (preg_match("/php/i", "PHP is the web scripting language of choice.")) {
echo "A match was found.";
} else {
echo "A match was not found.";
}
?>
<?php
/* The \b in the pattern indicates a word boundary, so only the distinct
* word "web" is matched, and not a word partial like "webbing" or "cobweb" */
if (preg_match("/\bweb\b/i", "PHP is the web scripting language of choice.")) {
echo "A match was found.";
} else {
echo "A match was not found.";
}
if (preg_match("/\bweb\b/i", "PHP is the website scripting language of choice.")) {
echo "A match was found.";
} else {
echo "A match was not found.";
}
?>
<?php
// get host name from URL
preg_match('@^(?:http://)?([^/]+)@i',
"http://www.php.net/index.html", $matches);
$host = $matches[1];
// get last two segments of host name
preg_match('/[^.]+\.[^.]+$/', $host, $matches);
echo "domain name is: {$matches[0]}\n";
?>
The above example will output:
domain name is: php.net
Do not use preg_match() if you only want to check if one string is contained in another string. Use strpos() or strstr() instead as they will be faster.