Javascript debugger
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As said before, references aren't pointers. That means, the following construct won't do what you expect:
<?php
function foo(&$var)
{
$var =& $GLOBALS["baz"];
}
foo($bar);
?>
What happens is that $var
in
foo
will be bound with
$bar
in caller, but then it will be
re-bound with $GLOBALS["baz"]
. There's no way
to bind $bar
in the calling scope to something else
using the reference mechanism, since $bar
is not
available in the function foo
(it is represented by
$var
, but $var
has only
variable contents and not name-to-value binding in the calling
symbol table).
You can use returning
references to reference variables selected by the function.